(20-r)^(1/2)=r

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Solution for (20-r)^(1/2)=r equation: 


D( r )

20-r < 0

20-r < 0

20-r < 0

20-r < 0

-r < -20 // * -1

r > 20

r in (-oo:20>

(20-r)^(1/2) = r // - r

(20-r)^(1/2)-r = 0

(20-r)^(1/2) = -r // + r

(20-r)^(1/2) = r // ^ 2

abs(20-r) = r^2 // - r^2

abs(20-r)-r^2 = 0

r in (-oo:+oo)

abs(20-r)

20-r >= 0

20-r >= 0

-r >= -20 // * -1

r <= 20

r in (-oo:20>

20-r^2-r = 0

r in (20:+oo)

r-r^2-20 = 0

abs(20-r)-r^2 = 0


/
| 20-r^2-r = 0 i r in (-oo:20>
| r-r^2-20 = 0 i r in (20:+oo)


r in (-oo:20>

20-r^2-r = 0

DELTA = (-1)^2-(-1*4*20)

DELTA = 81

DELTA > 0

r = (81^(1/2)+1)/(-1*2) or r = (1-81^(1/2))/(-1*2)

r = -5 or r = 4

r in (20:+oo)

r-r^2-20 = 0

DELTA = 1^2-(-20*(-1)*4)

DELTA = -79

DELTA < 0

r in { -5, 4 }

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